The density of the dead sea is 1.24x10^3 kg m^-3. A wooden board with an area of 2.5m^2 is dropped in the Dead Sea. Calculate the proportion that would float above the surface.

Density of wood= 800kg m^-3

Proportion submersed = density of wood/density of Dead Sea

= 800/(1.24 *10^3)
~ 0.65 or 65 %
So the proportion above the surface would be 1 minus that.

To calculate the proportion of the wooden board that floats above the surface of the Dead Sea, we need to compare the density of the wood to the density of the Dead Sea water.

The density of the wooden board is given as 800 kg/m^3, while the density of the Dead Sea water is given as 1.24 x 10^3 kg/m^3.

The proportion of the board that would float above the surface can be determined by comparing the two densities. If the density of the board is less than the density of the water, then it will float. If the density of the board is greater than the density of the water, then it will sink.

In this case, the density of the wooden board (800 kg/m^3) is less than the density of the Dead Sea water (1.24 x 10^3 kg/m^3). Therefore, the wooden board will float.

To calculate the proportion that would float above the surface, we need to find the difference in density between the wooden board and the Dead Sea water.

Density of the wood = 800 kg/m^3
Density of the Dead Sea water = 1.24 x 10^3 kg/m^3

Difference in density = Density of the Dead Sea water - Density of the wood
= (1.24 x 10^3 kg/m^3) - (800 kg/m^3)
= 4.4 x 10^2 kg/m^3

This difference in density tells us that the Dead Sea water can support an additional 4.4 x 10^2 kg/m^3 above the density of the wooden board.

To calculate the proportion that would float above the surface, we divide the difference in density by the density of the Dead Sea water:

Proportion that would float = (Difference in density) / (Density of the Dead Sea water)
= (4.4 x 10^2 kg/m^3) / (1.24 x 10^3 kg/m^3)
≈ 0.354

Therefore, approximately 35.4% of the wooden board would float above the surface of the Dead Sea.