Algebra2

Find the values of the inverse function in radians. 1. sin^-1(0.65)?

a. 0.71+2pi n and -0.71+2pi n
b. 0.71+2pi n and -3.85+2pi n
c. 0.86+2pi n and -0.86 +2pi n
d. -0.61+2pi n and 2.54+2pi n

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1. Nope. Those answers are in QI and QIV

The solutions are in QI and QII:

sin(.71) = .65
so the solutions are

.71 + 2nπ
pi-.71 + 2nπ = 2.4 + 2nπ

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posted by Steve
2. The primary solutions are
.71 and π-.71
or
.71 and 2.43

so I would state it as
.71 + 2πn and 2.43 + 2πn , which is a variation of B

so you are correct, but I find their choice puzzling
(notice -3.85 + 2π = 2.43)

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posted by Reiny
3. thank you

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posted by Steve

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