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Algebra 2
Find the values of the inverse function in radians. sin^1(0.65) a. 0.71+2pi n and 0.71+2pi n b. 0.71+2pi n and 3.85+2pi n c. 0.86+2pi n and 0.86 +2pi n d. 0.61+2pi n and 2.54+2pi n 2. tan^1(0.09) a.0.09+2pi n b. no such
asked by Fading on May 21, 2017 
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For questions 2 and 3, use a calculator to find the values of the inverse function in radians. sin^1(0.65) 0.71 + 2pi n and –0.71 + 2 pi n 0.71 + 2 pi n and –3.85 + 2 pi n 0.86 + 2pi n and –0.86 + 2pi n –0.61 + 2pi n and
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Find the values of the inverse function in radians. tan^1(0.09) answer choices: a.0.09+2pi n b. no such angle exists c.1.48+ pi n d. 0.09+ pi n My answer is D
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Consider the function f(x)=sin(1/x) Find a sequence of xvalues that approach 0 such that (1) sin (1/x)=0 {Hint: Use the fact that sin(pi) = sin(2pi)=sin(3pi)=...=sin(npi)=0} (2) sin (1/x)=1 {Hint: Use the fact that sin(npi)/2)=1
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Consider the function f(x)=sin(1/x) Find a sequence of xvalues that approach 0 such that (1) sin (1/x)=0 {Hint: Use the fact that sin(pi) = sin(2pi)=sin(3pi)=...=sin(npi)=0} (2) sin (1/x)=1 {Hint: Use the fact that sin(npi)/2)=1
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