Given that the line y=mx+c is a tangent to the circle
(x-a)^2+(y-b)^2 = r^2
show that:
(1-m^2)r^2=(c-b+ma)^2
Please Help and sorry for the inconvenience
Steve did this same question here:
http://www.jiskha.com/display.cgi?id=1493739139
(x-a)^2+(y-b)^2 = r^2
show that:
(1-m^2)r^2=(c-b+ma)^2
Please Help and sorry for the inconvenience
http://www.jiskha.com/display.cgi?id=1493739139