PHYSICS

Particles 1 and 2, each of mass m, are attached to the ends of a rigid massless rod of length L1 + L2, with L1 = 19 cm and L2 = 75 cm. The rod is held horizontally on the fulcrum and then released. What is the magnitude of the initial acceleration of particle 1? What is the magnitude of the initial acceleration of particle 2?
>>>>>>>
I = mL^2, L=L1+L2
I am not given mass and the answer needs to be numerical.
Tnet=I * alpha

How do I find the initial acceleration?

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asked by Calvin
  1. F=ma o---^---------o
    Assume m=1kg
    F=9.8N for both
    T=9.8*r T1=9.8(.19) T2=9.8(.75)
    Sum T=9.8(.75-.19)=Ttotal

    Ttotal=I(alpha)

    I=sum(mr^2) = r1^2+r2^2

    alpha=Ttotal/I

    a=alpha*r a1=alpha*(.19) a2=alpha*(.75)

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    posted by RAGADA

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