A pentagon can be divided into 5 congruent triangles. The function y=5 tan theta models the height of each triangle. What is the area of the pentagon if theta = 54 degrees?
since everyone is incompetent and didn't give the quiz answers, here they are for Lesson6; The Tangent Function
1. D
2. D
3. C
4. B
5. C
6. B
7. B
8. B
9. D
10. C
11. B
just wanted to help you all out since I had much help before this thanks to u guys. ps. I used photomath on the equations and it gave me the answers.
Just finished Lesson 6 The Tangent Function Quiz Part 1 and wanted to give a more user-friendly set of answers.
1. D(1)
2. D(y=2sinO/2)
3. C
4. C (amplitude=3)
5. C (-sqrt(3))
6. B (sqrt(3)/3)
7. B
8. B (tan 1/2 O)
9. C (172 ft^2)
10. B (3.64)
my mans Jesus got the wrong test, I’ll finish taking it and let u know.
I think it is 172 ft^2
I believe if you are on "Lesson 6: The Tangent Function Quiz Part 1," then your answer to that question will be: 172 ft².
The steps are as follows:
> Area of a triangle equation:
> A = (1/2)bh
> b=2×(5 ft), h=(5 ft)tan(54°)
> A = (1/2)(2×5 ft)(5 ft)(tan(54°)
> A = 25×tan(54°) ft²
The equation is that there are five congruent triangles that make up the pentagon, so you would plug in the numbers and come up with 172 ft².
I hope that made sense? I'm not a mathematical expert, so I can't explain it as clearly as them. You may want to review this with your math teacher as well, as they are there to help you! 😄