the force E needed to make a machine pull a load is partly constant and partly varies as the load to be pulled itself.when the load is 20g,the force needed is 1.4n,where as the force needed for 30g load is 2N.
Find the:
A)law connecting the load and the force
B)force for the load of 50g?
E = a+bL
1.4 = a+0.02b
2 = a+0.03b
subtract, and you have
0.6 = 0.01b
b = 60
so a = 0.2
E = 0.2 + 60L
Please why did you convert the 20N and the 30N
To find the law connecting the load and the force, we can start by expressing the force as the sum of two parts - the constant part and the variable part.
Let's denote the constant part of the force as Fc and the variable part as Fv.
Given that when the load is 20g, the force needed is 1.4N, we can write the equation as:
1.4N = Fc + Fv --(1)
Similarly, when the load is 30g, the force needed is 2N:
2N = Fc + Fv --(2)
To find the values of Fc and Fv, we can subtract equation (1) from equation (2):
2N - 1.4N = (Fc + Fv) - (Fc + Fv)
0.6N = 0
This suggests that the variable part of the force, Fv, is 0. The force needed to pull the load is entirely dependent on the constant part, Fc.
From equation (1), we know that Fc + 0 = 1.4N, so Fc = 1.4N.
Therefore, the law connecting the load and the force is:
Force (F) = 1.4N
To find the force for a load of 50g:
Force (F) = 1.4N
So, the force needed for a 50g load would also be 1.4N.
To find the law connecting the load and the force, we need to examine the relationship between the load and the force needed for different loads. Let's analyze the given data:
When the load is 20g, the force needed is 1.4N.
When the load is 30g, the force needed is 2N.
From this data, we can identify that the force needed increases as the load increases.
To determine the law connecting the load and the force, we'll calculate the change in force divided by the change in load.
Change in force = 2N - 1.4N = 0.6N
Change in load = 30g - 20g = 10g
Now we can find the ratio between the change in force and the change in load:
Ratio = (Change in force) / (Change in load)
= 0.6N / 10g
= 0.06N/g
The ratio is constant, meaning the force needed is directly proportional to the load. Therefore, the law connecting the load and the force is:
Force = (Constant part of force) + (Variable part of force)
= (0.06N/g * Load) + (Constant part of force)
To find the force for a load of 50g, we can substitute the load value into the equation:
Force = (0.06N/g * 50g) + (Constant part of force)
= 3N + (Constant part of force)
Unfortunately, we don't have enough information to determine the constant part of the force. Thus, we cannot find the force for a load of 50g based on the given information.