four diesel ships left a port at noon;january2,1953.the first ship returns to this port every 4 weeks, the second every 8, the third every 12,and the fourth every 16.when did all four ships meet again in the port?
The number of weeks later would be the lowest common multiple of 4,8,12 and 16.
That number would have to have as prime factors at least four 2's, and one 3. That means the ships return together
2^4 x 3 = ? weeks later.
Assume it is not a leap year
so the answer is 48 but how many days was in the year; with leep years
What is 48 weeks after Janaury 2?
1953 was not a leap year.
You do the counting. Don't use a 2008 calendar.
To find the date when all four ships meet again in the port, we need to find the least common multiple (LCM) of the four intervals at which the ships return to the port.
The LCM of 4, 8, 12, and 16 is 48. This means that all four ships will meet again in the port after 48 weeks.
Now, to determine the date when they meet again, we need to add 48 weeks to the initial date of January 2, 1953. However, we must also consider the days of the week.
Since the ships left the port at noon on January 2, 1953, we will assume that it was a Thursday (although we don't have information about the day of the week in the question). We will count weeks, starting from Thursday, in order to determine the final date.
Adding 48 weeks to January 2, 1953, we get:
January 2, 1953 + 48 weeks = October 22, 1954
Therefore, all four ships will meet again in the port on October 22, 1954.