What is the molar mass of feso4 . 7h2o
Add up the atomic masses.
Fe + S + 4*O + 14*H + 7*O = ?
To find the molar mass of FeSO4 . 7H2O (iron(II) sulfate heptahydrate), follow these steps:
1. Start by calculating the molar mass of each component separately.
- Molar mass of Fe (iron): You can find the atomic mass of iron on the periodic table. In this case, it is 55.845 g/mol.
- Molar mass of S (sulfur): The atomic mass of sulfur is 32.06 g/mol.
- Molar mass of O (oxygen): Oxygen has an atomic mass of 16.00 g/mol.
- Molar mass of H (hydrogen): Hydrogen has an atomic mass of 1.008 g/mol.
Additionally, we need to account for the 7 water molecules (H2O) in the compound. Each water molecule has a molar mass of (2H x 1.008 g/mol) + (1O x 16.00 g/mol) = 18.02 g/mol.
2. Now, multiply the molar mass of each element by the number of atoms of that element in the compound.
- Fe: 1 atom x molar mass of Fe = 1 x 55.845 g/mol = 55.845 g/mol
- S: 1 atom x molar mass of S = 1 x 32.06 g/mol = 32.06 g/mol
- O: 4 atoms x molar mass of O = 4 x 16.00 g/mol = 64.00 g/mol
- H: 14 atoms x molar mass of H = 14 x 1.008 g/mol = 14.112 g/mol
- H2O: 7 molecules x molar mass of H2O = 7 x 18.02 g/mol = 126.14 g/mol
3. Finally, add up the molar masses of each component to get the total molar mass of the compound.
Total molar mass = molar mass of Fe + molar mass of S + molar mass of O + molar mass of H + molar mass of H2O
= 55.845 g/mol + 32.06 g/mol + 64.00 g/mol + 14.112 g/mol + 126.14 g/mol
Therefore, the molar mass of FeSO4 . 7H2O is 292.22 g/mol.