chemistry

The oxidation number of sulphur in CuSO4.5H2O is ......

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  1. Cu is +2
    S is S
    O is -2. 4*-2 = -8
    All compounds add to zero.
    Cu + S + 4*-2 = 0
    2 + S +(-8) = 0
    2 + S + -8 = 0
    Solve for S.
    S = 0 - 2 + 8 = ?

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  2. 10

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  3. R7o3b6e2l5

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  4. 0973625793

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  5. +6 because SO4 has no bracket

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  6. The oxidizing agent is oxizided by the reduced agent

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  7. Ansewor

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  8. What about Hydrogen

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  9. What about Hydrogen

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