Two 100 kg ball are mounted on a seesaw and seesaw is in balanced position and balls can move freely on the surface.How much force I should applied on the right arm of seesaw so that the left side ball could jump up to 5 centimeter in the Air.
To determine how much force you need to apply on the right arm of the seesaw to make the left side ball jump up to 5 centimeters in the air, we need to consider the principles of conservation of energy and Newton's laws of motion.
First, let's consider the initial state of the system. The seesaw is in a balanced position, which means that the total torque and total force acting on the seesaw are zero. The two 100 kg balls are on opposite sides of the seesaw, symmetrically placed.
When the left ball jumps up, it gains potential energy while losing kinetic energy. The force you apply to the right arm of the seesaw can be calculated using the following steps:
1. Calculate the change in potential energy of the left ball: ΔPE = m × g × h
- m is the mass of the left ball (100 kg)
- g is the acceleration due to gravity (9.8 m/s²)
- h is the height that the left ball needs to jump (5 cm = 0.05 m)
ΔPE = 100 kg × 9.8 m/s² × 0.05 m = 49 J
2. According to the principle of conservation of energy, the work done by the force applied to the right arm of the seesaw should be equal to the change in potential energy of the left ball: Work = ΔPE
Work = ΔPE = 49 J
3. The work done