If the energy used to heat up a block of 2kg of copper is 115.8 kJ, what is the temperature it was heated to if the starting temperature was 100oC and the specific heat capacity is 386 J/kgK.

To find the final temperature that the block of copper was heated to, we can use the equation:

Q = m * c * ΔT

Where:
Q is the energy transferred (in joules),
m is the mass of the object (in kilograms),
c is the specific heat capacity of the material (in joules per kilogram per degree Celsius),
ΔT is the change in temperature (in degrees Celsius).

In this case, we are given:
Q = 115.8 kJ = 115.8 * 1000 J (converting kilojoules to joules)
m = 2 kg
c = 386 J/kgK (specific heat capacity of copper)
Initial temperature, Ti = 100 °C

We need to rearrange the equation to solve for ΔT:

ΔT = Q / (m * c)

Plugging in the given values:

ΔT = 115.8 * 1000 J / (2 kg * 386 J/kgK)

Simplifying the equation:

ΔT = 115800 J / (772 J/K)

ΔT ≈ 150.26 K

To find the final temperature, Tf, we add this change in temperature to the initial temperature:

Tf = Ti + ΔT
Tf = 100 °C + 150.26 K

Note that Celsius and Kelvin have the same scale, so we can directly add them:

Tf ≈ 250.26 °C

Therefore, the block of copper was heated to approximately 250.26 °C.