this is my question
Calculate the hydronium ion consentration and the hydroxide concentration in blood in which the PH is 7.3.
I don't have invlog on my calculator so I hit log(7.3)= .863 for hydronium. Is this dumb for me to do?
That is dumb for you to do.
Get a calc that has an INV key. Mine costs eight dollars.
concentration= invlog (-7.3)= 5.01?E-08
Do you have a 2nd key, and a log key?
normally, 2nd Log is same as INVLOG
yes when I press 2nd then log I get 10^, is this correct?
In order to get antilog on mine I punch the 10x key. And a pH of 7.3 is hydroniuim of 5.01E-8.
ok I got that part. now how can I find Hydroxide concentration from this?
Two ways.
#1. (H^+)(OH^-) = 1 x 10^-14.
You know (H^+).
#2. pH + pOH = pKw = 14
You know pH, so subtract from 14 to get pOH. Then pOH = -log(OH^-).
PH + pOH = pKw =14
7.3 + pOH =pKw =14
7.3 - 14 = 6.7
pOH = -log(OH^-)
6.7 = -log(1.00 x 10^-14)
pOH = 1.92 x 10^6? I'm stuck
PH + pOH = pKw =14
7.3 + pOH =pKw =14
7.3 - 14 = 6.7
pOH = -log(OH^-) OK to here
6.7 = -log(1.00 x 10^-14)
pOH = 1.92 x 10^6? I'm stuck
pOH = -log(OH^-)
6.70 = -log(OH^-)
-6.70 = log(OH^-)
1.996 x 10^-7 = round to
2 x 10^-7 = (OH^-)
To find the concentration of hydroxide (OH-) in the blood, you can use one of the two methods mentioned. Let's go through both of them.
Method 1:
(H^+)(OH^-) = 1 x 10^-14
Since you know the hydronium ion concentration (H+), which is 5.01E-8, you can rearrange the equation and solve for (OH-):
(OH^-) = 1 x 10^-14 / (H^+)
(OH^-) = 1 x 10^-14 / 5.01E-8
(OH^-) ≈ 1.996 x 10^-7, which can be rounded to 2 x 10^-7
So, the hydroxide concentration in the blood is approximately 2 x 10^-7.
Method 2:
pH + pOH = pKw = 14
Since you know the pH, which is 7.3, you can subtract it from 14 to get the pOH:
pOH = 14 - 7.3
pOH ≈ 6.7
Now, you can calculate the concentration of hydroxide (OH-) using the pOH:
(OH^-) = 10^(-pOH)
(OH^-) = 10^(-6.7)
(OH^-) ≈ 1.996 x 10^-7, which again can be rounded to 2 x 10^-7
So, both methods give the same result. The hydroxide concentration in the blood is approximately 2 x 10^-7.
To find the hydroxide concentration, you can use the equation (H^+)(OH^-) = 1 x 10^-14. Since you know the hydronium ion concentration is 5.01E-8, you can solve for the hydroxide concentration:
(H^+)(OH^-) = 1 x 10^-14
(5.01E-8)(OH^-) = 1 x 10^-14
Divide both sides of the equation by 5.01E-8 to solve for OH^-:
OH^- = (1 x 10^-14) / (5.01E-8)
OH^- = 2.00 x 10^-7
So the hydroxide concentration in blood is approximately 2.00 x 10^-7 M.