I am really confused on this question can some one help me out please
the length of a rectangular playing field is 5 ft less than twice its width If the perimeter of the playing field is 230 ft. find the length and width of the field.
I believe i am suppose to start with
P+2w+2L
I am lost after that please help
2L + 2W= P
but L+5= 2w
so
2L + L+5= P so figure what L is.
lets see if i am done this right
2L+L+5=230
3L+5=230
3L=-5+230
3L=225
3L/3=225/3
L=225/3
L=75
did I do this right
Then you must calculate W.
Then see if 2L + 2W = 230.
To solve the problem, you first set up the equations based on the information given. Let's call the width of the field "W" and the length "L."
According to the problem, the length is 5 feet less than twice the width, which can be expressed as L = 2W - 5.
The perimeter of a rectangle is calculated by adding up all the sides. In this case, it is given as 230 feet, so the equation for the perimeter is: 2L + 2W = 230.
Now, substitute the value of L from the first equation into the second equation.
2(2W - 5) + 2W = 230.
Simplify the equation:
4W - 10 + 2W = 230.
Combine like terms:
6W - 10 = 230.
Add 10 to both sides:
6W = 240.
Divide both sides by 6:
W = 40.
Now that you've found the width, substitute this value back into the first equation to find the length.
L = 2W - 5 = 2(40) - 5 = 80 - 5 = 75.
So, the dimensions of the rectangular playing field are 75 feet for the length and 40 feet for the width.
To check if the answer is correct, substitute the values of L and W into the perimeter equation:
2L + 2W = 2(75) + 2(40) = 150 + 80 = 230.
Since the calculated perimeter matches the given perimeter, the solution is correct.