Please help ~~
Because i don't ever know the reaction in organic compound ..
Do anyone has the data bank of the organic chemicals ?
I cannot find out what are the compound in the reaction with it ~~
1. What do butylamine give when it is dissolved in water ?
A nearly pH10 solution was obtained. There may be some OH- ions in the equation.
2. When phenylamine react with hydrochloric acid ,the color of the solution turns from black to pure brown .How can i present it in equation ? Also, when the solution was placed to evaporate, a brown solid is obtained.What is it?
Moreover, does butylamine react with hydrochloric acid?There is no observable changes , it remains colorless.
3. When copper(II) sulphate solution react with phenylamide, a yellowish-green solid form. Besides, it seems that there is also some black solid. What are they ?
4.When copper(II) sulphate solution react with butylamide, some blue precipitates were formed and then redissolved to give a colorless solution. What have been happened during the reaction ? What are the products in the reaction ?
5. When copper(II) sulphate solution react with ammonia solusion,the solution turns to deep blue andthen be pale blue. What were formed in the reaction ?
Please help me before i've found the data ...plz plz plz plz .......
You don't need a data bank of organic chemicals. You need to know the reactions involved. I can't help with all of them.
Please make your posts just one question to the post. It takes too much time to answer five questions and if we don't have that much time we may pass the question by and you don't get any help.
1. I assume you mean n-butyl amine.
CH3CH2CH2CH2NH2. Which I will call BNH2.
BNH2 hydrolyzes in water to form the NH3^+ ion and OH.
BNH2 + HOH ==> BNH3^+ + OH^-
From question 2, you say there is no observable reaction BUT you can test the water solution an know it is basic so there MUST have been a reaction in order to produce the OH^-.
2. Phenylamine is just another amine (although an aromatic amine instead of aliphatic as in the case of butylamine. So the same reaction.
C6H5NH2 + HCl ==> C6H5NH3^+ + Cl^-
5. Cu^+2 + 4NH3 ==> Cu(NH3)4^+2
The pale blue of the copper(II) ion changes to the deep blue color of the copper(II) ammine complex ion.
For the other copper tests, look in your text for the identification of amides and see if you can find anything there. For example, Fehlings solution identifies reducing sugars and contains CuSO4 but I don't know those tests for amides.
Sure, I can help you with the reactions of the organic compounds you mentioned. Here are the step-by-step explanations for each reaction:
1. When butylamine is dissolved in water, it can undergo hydrolysis to form an alkaline solution. Butylamine contains a basic amine group (NH2), which can accept a proton from water, producing OH- ions. The equation for this reaction can be written as:
C4H9NH2 + H2O → C4H9NH3+ + OH-
The resulting solution will have a pH value close to 10 due to the presence of OH- ions.
2. When phenylamine (also known as aniline) reacts with hydrochloric acid, it undergoes a salt formation reaction. The amine group (NH2) in phenylamine reacts with H+ ions from hydrochloric acid to form a salt called anilinium chloride. This reaction can be represented as follows:
C6H5NH2 + HCl → C6H5NH3+ Cl-
The color change observed, from black to pure brown, may be due to the formation of the brown-colored salt.
Upon evaporating the solution, anilinium chloride will crystallize as a brown solid.
Regarding butylamine and hydrochloric acid, no significant observable changes occur, and the mixture remains colorless. This suggests that butylamine does not react significantly with hydrochloric acid.
3. When copper(II) sulphate solution reacts with phenylamine, a yellowish-green solid forms. This solid is likely a copper(II) complex with phenylamine, which has a greenish color. The reaction can be represented as:
C6H5NH2 + CuSO4 → [Cu(C6H5NH2)4]2+ + SO4^2-
Additionally, the formation of a black solid indicates the possible formation of a precipitate or another complex involving copper.
4. When copper(II) sulphate solution reacts with butylamine, blue precipitates are initially formed. These blue precipitates are likely a copper(II) complex with butylamine. However, upon further reaction, the blue precipitate redissolves to give a colorless solution. This suggests that the blue precipitate is soluble in excess butylamine. The reaction and products can be described as follows:
C4H9NH2 + CuSO4 → [Cu(C4H9NH2)4]2+ + SO4^2-
[Cu(C4H9NH2)4]2+ (blue precipitate) + excess C4H9NH2 → [Cu(C4H9NH2)4]^2+(aq) (colorless solution)
5. When copper(II) sulphate solution reacts with ammonia solution (NH3), a deep blue solution is initially formed due to the formation of a copper(II) complex called tetraamminecopper(II) ion ([Cu(NH3)4]2+). However, upon dilution or excess ammonia, the deep blue color becomes pale blue due to the formation of a diluted complex. The reactions can be represented as follows:
CuSO4 + 4NH3 → [Cu(NH3)4]SO4
[Cu(NH3)4]SO4 + excess NH3 → [Cu(NH3)4]2+ (deep blue) + SO4^2-
[Cu(NH3)4]2+ + excess NH3 → [Cu(NH3)4(OH)2]2+ (pale blue)
These reactions describe the interactions between the mentioned organic compounds and inorganic compounds. Please note that the equations provided are simplified representations, and the actual reactions may involve more complex species and equilibria.
I understand that you have several questions about reactions involving different organic compounds and their products. It seems like you are looking for a database of organic chemicals to find the compounds involved in these reactions. However, I can help you understand how to determine the possible products and reactions without relying on a specific database. Here's how you can approach these questions:
1. When butylamine is dissolved in water, it can ionize to form butylammonium ions (C4H9NH3+) and OH- ions. The basicity of butylamine leads to the formation of OH- ions, resulting in a nearly pH10 solution.
2. When phenylamine reacts with hydrochloric acid (HCl), it forms phenylammonium chloride (C6H5NH3Cl). The equation can be represented as: C6H5NH2 + HCl -> C6H5NH3Cl. When the solution is evaporated, the resulting brown solid is likely the phenylammonium chloride.
Regarding the reaction of butylamine with hydrochloric acid, if there are no observable changes and the solution remains colorless, it suggests that there might not be a significant reaction between them.
3. The reaction between copper(II) sulfate solution and phenylamide can result in the formation of a yellowish-green solid, which could be a copper(II) phenylamide complex. The black solid might be a byproduct formed during the reaction or an impurity.
4. When copper(II) sulfate solution reacts with butylamide, blue precipitates are formed initially, indicating the formation of a copper(II) butylamide complex. However, the subsequent dissolution of the blue precipitates to give a colorless solution suggests that the complex may be unstable and decomposes, resulting in a colorless product.
5. When copper(II) sulfate solution reacts with ammonia solution, a deep blue solution is initially formed due to the formation of a copper(II) ammonia complex. However, over time, the color changes to pale blue, indicating the conversion of the complex into another form, possibly a less stable copper ammine complex.
Please note that these are generalized explanations based on the given information. The specific conditions and concentrations of reactants can influence the outcome of a reaction. It's always recommended to refer to authoritative sources or literature for more precise information.