A mountain bike tire has a diameter of 26 inches. To the nearest foot, how far does the tire travel when it makes 32 revolutions?

32 * 26π in * 1ft/12in = 217.817 ft

To find how far the tire travels when it makes 32 revolutions, we need to calculate the circumference of the tire and multiply it by the number of revolutions.

The circumference of a circle can be found using the formula: C = 2πr, where C is the circumference and r is the radius.

Since we are given the diameter of the tire, which is 26 inches, we can calculate the radius by dividing the diameter by 2: r = 26 / 2 = 13 inches.

Now we can calculate the circumference of the tire: C = 2π * 13 = 26π inches.

To convert the distance traveled to feet, we divide the distance in inches by 12, since there are 12 inches in a foot. Therefore, the distance traveled in feet is (26π / 12) * 32.

Calculating this expression will give us the answer:

Distance traveled = (26π / 12) * 32.

Let's calculate this:
Distance traveled = (26 * 3.14159 / 12) * 32.

Distance traveled = (81.681408 / 12) * 32.

Distance traveled = 6.806784 * 32.

Distance traveled ≈ 217.821728 inches.

To find the answer to the nearest foot, we need to convert inches to feet by dividing by 12 and round to the nearest foot:

Distance traveled = 217.821728 / 12.

Distance traveled ≈ 18.152728 feet.

Rounding to the nearest foot, the mountain bike tire travels approximately 18 feet when it makes 32 revolutions.