A container of volume 0.39 m3 contains 8.7 mol of argon gas at 32◦C. Assuming argon behaves as an ideal gas, find the total internal energy of this gas. Answer in units of J.Given: R = 8.31451 J/mol • K.

Internal energy per mole = Cv*T (for ideal gases), and

= (3/2) R T for monatomic gases (like argon)

Since you know the number of moles, you don't need to know the volume.

To find the total internal energy of the gas, we can use the equation:

U = (3/2) nRT

Where:
U is the total internal energy of the gas
n is the number of moles of gas
R is the ideal gas constant
T is the temperature in Kelvin

First, let's convert the temperature from Celsius to Kelvin. We add 273.15 to the temperature value:

T = 32 + 273.15 = 305.15 K

Now, we can substitute the given values into the equation:

U = (3/2) * (8.7 mol) * (8.31451 J/mol • K) * (305.15 K)

Simplifying the equation:

U = (3/2) * (8.7) * (8.31451) * (305.15)

U = 3 * 8.7 * 8.31451 * 305.15

U ≈ 65034.13 J

Therefore, the total internal energy of the gas is approximately 65034.13 J.