Would electrons be ejected from aluminum if the incident violet light has a wavelength of 4.00 x 10-7 m?

need about 4.2 eV for photoelectric effect - Aluminium

what is energy of 4*10^-7 meter photon?
6.6*10^-34*3*10^8/4*10^-7
= 4.9 * 10^-19 J

1 eV= 1.6020 × 10–19 J

so 4.9 /1.6 eV in photon

that looks less than required 4.2 eV