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calculus please help!!

Find the range of the function F(x)= definite integral from [-6,x] of sqrt(36-t^2)dt.

[0, 36π]

[0, 18π]***

[-6, 6]

[-6, 0]

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  1. i know this question has something to do with semicircles and radians. I got the starred answer as my own but I'm not sure if it's correct or how I got there. Help thanks!!

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  2. The region is a semi-circle of radius 6, so the area ranges from 0 to 18π

    The integral is the area moving from the left side to some point x in [-6,6].

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