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log10x+log4x=2. Find x value
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2 log(x) + log(4) + 1 = 2
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40 x^2 = 100
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x^(log10x)=100
I'm not sure how to do this at all...
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If Log10x = -7 how do I work out the value of x?
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Log10x = -7 is the same as 10^-7 = x or x = 0.0000001
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You should use parentheses to indicate just what you are taking the log of. Is it 4, 4x or 4x^3? I
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log4x^4 + log4^2 = 3
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log4x^4 = log4 + 4logx log4^2 = 2log4 log4 + 4logx + 2log4 = 3 3log4 + 4logx = 3 4logx = 3(1-log4)
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solve the equation.
log2(x+4)-log4x=2 please show work
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Compare the graphs of the logarithimic functions f(x)=log7x and g(x)=log4x. For what values of x is f=g, f>g, and f<g? explain
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The graphs of logarithmic functions have some distinct characteristics. For f(x) = log7x, the base
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log2(log4x) = 1
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and by the bases are 2 and 4 I mean they're like the small numbers where the standard would be 10
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compare the graphs of the logarithmic functions f(x)=log7x and g(x)=log4x. for what values of x is f=g, and f>g, and f<g.
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To compare the graphs of the logarithmic functions f(x) = log7x and g(x) = log4x, we first need to
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log10x + log10(x+1)=1
In other words log base 10 + log base 10(x+1)=1 I need to show it algebraically not using calculator Thanks
helo sir/madam
can u help me to solve this problem sOLVE 2log 15 +log(5-x)- log4x=2
I am having trouble figuring out how to solve these logarithms. Could someone please help!
log2(log4x)=1 and solve for x and y:
I am having trouble figuring out how to solve these logarithms. Could someone please help!
log2(log4x)=1 and solve for x and y:
