You place a bet on the number 21 in roulette. The probability of winning is 1 38 , and the company hosting the casino night for a city fundraiser gives the payoff odds as 35:1. What are the odds that the ball will land on the number 21?
1:37
1:38
1:35
1:21
I disagree,
Odds and probability are defined slightly different.
The odds of some event happening
= prob( event) : prob(not the event)
so if prob(a 21 ) = 1/38
then the prob(not a 21 ) = 1 - 1/38 = 37/38
odds in favour of a 21 = (1/38) / (37/38)
= (1/38)(38/37)
= 1 : 37
The probability of winning is 1 38
so the odds are one in thirty-eight
1:38 ???
thanks
To calculate the odds that the ball will land on the number 21 in roulette, you need to use the formula:
Odds = Probability of Winning / Probability of Losing
In this case, the probability of winning is 1 out of 38, since there are 38 numbers on the roulette wheel. The probability of losing is therefore 37 out of 38, as there are 37 other numbers that the ball could land on.
Using the formula, the odds are:
Odds = 1/37
So the correct answer is 1:37.