Ben is four years older than Juan. In two years, their ages will total 50. How old is each now?
Juan's present age --- x
Ben's present age ---- x+4
in two years:
Juan ----- x+2
Ben -------x=4+2 = x+6
x+2 + x+6 = 50
continue
To solve this problem, we can set up a system of equations based on the given information.
Let's assume that Juan's current age is "x" years. Since Ben is four years older than Juan, Ben's current age would be "x + 4" years.
In two years, Juan's age will be "x + 2" years, and Ben's age will be "x + 4 + 2" years, which simplifies to "x + 6" years.
According to the problem, the sum of their ages in two years will be 50. So, we can write the equation:
(x + 2) + (x + 6) = 50
Simplifying the equation, we have:
2x + 8 = 50
Now, subtracting 8 from both sides:
2x = 42
Finally, divide both sides by 2:
x = 21
Juan's current age is 21 years. Since Ben is four years older, his current age is 21 + 4 = 25 years.
So, Juan is currently 21 years old, and Ben is currently 25 years old.