Consider a pipe with a length of 57.5 cm. If the temperature of the air is 21.5+B degrees C and the pipe is closed in one end and open in the other, what is the frequency of the third harmonic for the pipe? Post your answer in hertz (Hz) and with 3 significant figures.

To find the frequency of the third harmonic for the pipe, we need to use the formula:

f = (nv) / (4L)

Where:
f is the frequency of the harmonic
n is the harmonic number (in this case, it's 3 for the third harmonic)
v is the speed of sound in air at the given temperature and B degrees C
L is the length of the pipe

To start, we need to find the speed of sound in air at the given temperature. The speed of sound in air is approximately 331.5 + 0.6B meters per second (m/s). Since the temperature given is in degrees Celsius, we need to convert it to Kelvin by adding 273.15:

Temperature in Kelvin = 21.5 + B + 273.15

Next, we convert the length of the pipe from centimeters to meters:

Length of the pipe in meters = 57.5 cm / 100

Now we have all the values we need to find the frequency:

f = (3 * v) / (4 * L)

Substitute the values of v and L into the formula:

f = (3 * (331.5 + 0.6B + 273.15)) / (4 * 0.575)

Calculate the frequency using the given value of B, then round it to three significant figures to get the final answer in Hz.