7. If 60 ml of water contains 12% of chlorine, how much water must be added in
order to create a 8% chlorine solution?
30 ml
To solve this problem, we need to determine how much water needs to be added to the original solution to create a new solution with a lower concentration of chlorine. Here's how we can approach it:
Step 1: Determine the amount of chlorine in the original solution.
- We know that 60 ml of water contains 12% chlorine.
- Therefore, the amount of chlorine in the original solution is 60 ml * 0.12 = 7.2 ml.
Step 2: Determine the final volume of the new solution.
- Since we only want to change the concentration of chlorine and not the total volume, the final volume of the new solution will be the same as the original solution, which is 60 ml.
Step 3: Determine the amount of chlorine in the final solution.
- We want the final concentration of chlorine to be 8% in the 60 ml solution.
- Therefore, the amount of chlorine in the final solution should be 60 ml * 0.08 = 4.8 ml.
Step 4: Calculate the amount of water that needs to be added.
- The amount of water we need to add is the difference between the final volume of the solution and the amount of chlorine in the final solution.
- Therefore, the amount of water to be added is 60 ml - 4.8 ml = 55.2 ml.
So, in order to create an 8% chlorine solution, you would need to add 55.2 ml of water to the original 60 ml solution.
mL1 x %1 = mL2 x %2
60 x 0.12 = mL2 x 8
mL2 is TOTAL. You already had 60. So you must add ______?