If you flip three fair coins, what is the probability that you'll get a head on the first flip, a tail on the second flip, and another head on the third flip?
To find the probability of getting a head on the first flip, a tail on the second flip, and another head on the third flip of three fair coins, we need to calculate the probability of each individual event and then multiply them together.
The probability of getting a head on a fair coin flip is 1/2 because there are two equally likely outcomes - heads or tails - and we want the probability of one specific outcome, which is heads.
Similarly, the probability of getting a tail on the second flip is also 1/2.
Multiplying these probabilities together, we get (1/2) * (1/2) = 1/4.
Now, we need to find the probability of getting another head on the third flip, and this probability remains 1/2.
Multiplying all the probabilities together, we have (1/2) * (1/2) * (1/2) = 1/8.
Therefore, the probability of getting a head on the first flip, a tail on the second flip, and another head on the third flip of three fair coins is 1/8 or 0.125, which is approximately 12.5%.
To find the probability of getting a specific sequence of coin flips, you multiply the probabilities of each individual flip.
In this case, the probability of getting a head on the first flip is 1/2 (since there are two equally likely outcomes: heads or tails).
The probability of getting a tail on the second flip is also 1/2.
The probability of getting another head on the third flip is 1/2.
Multiplying these probabilities together, we get:
(1/2) * (1/2) * (1/2) = 1/8
So the probability of getting a head on the first flip, a tail on the second flip, and another head on the third flip is 1/8.