# Physics

Suppose that you place a square block of wood with dimensions 12.0 cm x 12.0 cm x 6.0 cm
into some water as shown below. The wood has a density of 600 kg/m3. What is the distance from the bottom horizontal face of the block to the surface of the
water? (In other words, how much of the block’s height will be underwater?)

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1. figure the mass of the wood:
.12*.12*.06*600kg== 0.000864(600)= = 0.5184 kg

so now, the volume of water displaced must be 518cm
12*12*h=518 solve for h in cm

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2. Vb = L*W*h = 12 * 12 * 6 = 864 cm^3. = Vol. of the block.

Db/Dw * h = 600/1000 * 6cm = 3.6 cm submerged.

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posted by Henry
3. NOTE: My vol. calculation was not required.

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posted by Henry

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