Ashton and molly start out 97.2 miles apart .They begin riding their bicycles toward each other with Aston riding three mph faster than Molly. If they meet in three hours, how fast was each person riding?

Please help

distance=relativevelocity*time

97.2=(v+3+v)3
solve for v
2v+3=32.4
2v=29.4
v=14.2
and aston then is 17.2

Thank you

To solve this problem, we can use the formula: Distance = Rate * Time.

Let's assume Molly's rate is 'x' mph. Therefore, Ashton's rate would be 'x + 3' mph since he is riding three mph faster.

Now let's calculate the distances each person traveled in three hours:

Distance Molly traveled = Rate * Time = x * 3 = 3x miles.
Distance Ashton traveled = Rate * Time = (x + 3) * 3 = 3x + 9 miles.

Since they are riding towards each other, the sum of their distances should add up to 97.2 miles:

Distance Molly traveled + Distance Ashton traveled = 97.2.
3x + (3x + 9) = 97.2.
6x + 9 = 97.2.
6x = 97.2 - 9.
6x = 88.2.
x = 88.2 / 6.
x = 14.7.

Molly's rate is 14.7 mph.
Ashton's rate is 14.7 + 3 = 17.7 mph.

Therefore, Molly was riding at 14.7 mph and Ashton was riding at 17.7 mph.