Find all the solutions in the interval [0,2pi).

2sin2x - sqrt(2) = 0

sin2x = sqrt(2)/2

I'm confused by the double angle. Please help.

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asked by Travis
  1. so continue...

    sin2x =√2/2
    2x = 45º or 135º
    x = 22.5º or x = 67.5º

    in radians: x = pi/8 or 3pi/8

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    posted by Reiny
  2. But my calculator also shows 9pi/8 and 11pi/8. Why do you have to add pi?

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    posted by Travis
  3. ahh, smart calculator you got there.

    the period of sin2x is pi or 180 degrees

    so we have to add pi to each of our answers until we are no longer in the given domain.

    so x = pi/8, 3pi/8, 9pi/8 and 11pi/8

    I should have taken care of that in my first post , sorry

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    posted by Reiny
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  5. fgndboqt fwhgdlqyj czefhiko zykom piesg kcqiruf kmelqpvz

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