Evaluate the following statement (T/F/N), explain:

If you reduce by half the distance between two point charges, you double the magnitude of electrical force that each exerts on the other.

a ball of mass 0.220-kg that is moving with a speed of 5.5

true. force=a/distance^2

reduce distance by half, multiply the force by 2^2 = 4

k Q1 Q2 / d^2

The statement is true (T).

To understand why this statement is true, we need to consider the equation for the magnitude of the electrical force between two point charges, which is given by Coulomb's Law:

F = (k * |q1 * q2|) / r^2,

where F represents the force, k is the electrostatic constant (a constant value), |q1 * q2| represents the product of the magnitudes of the charges, and r^2 represents the square of the distance between the charges.

Now, let's consider what happens when we reduce the distance between the two charges by half. In this case, the new distance between the charges becomes (1/2)r, where r is the original distance.

If we substitute this new distance into Coulomb's Law, we have:

F' = (k * |q1 * q2|) / ((1/2)r)^2.

Simplifying this expression:

F' = (k * |q1 * q2|) / ((1/2)^2 * r^2).

F' = 4 * (k * |q1 * q2|) / r^2.

Now, compare the new force (F') to the original force (F):

F' = 4 * F.

We can see that F' is four times greater than F. Therefore, by reducing the distance between two point charges by half, we double the magnitude of the electrical force that each charge exerts on the other.