The work crew for the talent show at the local high school includes these members: 2 freshmen,4sophomores,8juniors,6 seniors.If the sponsor randomly chooses 1 member of the work crew to announce the act & 1 member to control the lighting, what is the probability that he will choose the 2 freshmen? total 2/20 1/10???? not sure of answer
there are 20 students. So, the chance of getting the two freshmen is
2/20 * 1/19 = 1/190
This just selection without replacement.
Find the Area to the nearest 100th with pi being 3.14 d=7m
To find the probability of choosing the two freshmen, we need to determine the total number of possible outcomes and the number of favorable outcomes.
First, let's find the total number of possible outcomes. In this case, the sponsor needs to choose one member to announce the act and one member to control the lighting. Since there are a total of 20 crew members, the sponsor has 20 options for the first choice.
For the second choice, there will be 19 remaining crew members to choose from since one member has already been selected for the first role.
Therefore, the total number of possible outcomes is 20 * 19 = 380.
Next, let's determine the number of favorable outcomes, which in this case is choosing the two freshmen members. We have been given that there are 2 freshmen members in the work crew.
The sponsor needs to choose one of the two freshmen members for the first role and one of the two remaining freshmen members for the second role. So, the number of favorable outcomes is 2 * 1 = 2.
Now, we can calculate the probability by dividing the number of favorable outcomes by the total number of possible outcomes.
Probability = Number of favorable outcomes / Total number of possible outcomes
= 2 / 380
= 1 / 190
Therefore, the probability that the sponsor will choose the two freshmen members is 1/190, or approximately 0.0053.