Find all the real zeros for the equation p(x)=x^3+4x^2+x-6
inspection shows 1 as a root (zero)
so (x - 1) is a factor
dividing p(x) by (x - 1) will leave a quadratic that can be broken down
so (x - 1) is a factor
dividing p(x) by (x - 1) will leave a quadratic that can be broken down