Suppose 20% of babies born are born early, 50% are born on time, and 30% are born late. A nurse uses a random-number table to find the experimental probability that of 5 births, at least 1 baby will be born early. The digits 0 and 1 represent babies born early. The digits 2, 3, 4, 5, and 6 represent babies born on time. The digits 7, 8, and 9 represent babies born late.
23059|14568|03489|01235
78234|24579|12456|34567
01785|13579|01458|23478
12359|01239|23567|13546
26789|24589|01238|23589
Find the experimental probability that of 5 babies born, at least 1 will be born early.
A:1/5
B:2/5
C:3/5
D:4/5
(I've tried this question, didn't get it, so I just guessed...I think it's C. Idk, just please help.)
Yes, A.
Um...Mrs. Sue? I know you're answering others but I need to know whether it's A.
Is that the correct answer?
Oh okay, nvm. My internet lagged so I guess it took awhile for your response. Thank you!
No.
Which fraction is 20%?
sooo the answer is---?
if we divide 1/5 we get 0.2 = multiply it by 100 you get 20%
so yes it is 1/5