a prismatic abject 8 thick by 8 wide by 16 long is weighed in water at a depth of 200 and found to weight 11Ib. what is its weight in air and its specific gravity?
afsfs
To find the weight of the prismatic object in air and its specific gravity, we need to use the principles of buoyancy and density.
1. Weight of the object in air:
The weight of the object in air can be calculated by subtracting the buoyant force acting on it in water from its actual weight in water.
Buoyant force = weight of water displaced by the object
Weight in air = Weight in water - Buoyant force
Given that the weight in water is 11 lb, we need to find the buoyant force acting on the object.
2. Buoyant force:
The buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.
Weight of water displaced = Density of water x Volume of the object
The density of water is approximately 62.4 lb/ft³. To calculate the volume of the object, we multiply its dimensions: 8 inches (1/12 ft) x 8 inches (1/12 ft) x 16 inches (1/12 ft).
Now, we can find the weight of water displaced and subtract it from the weight in water to get the weight of the object in air.
3. Specific gravity:
Specific gravity is the ratio of the density of a substance to the density of a reference substance, usually water.
Specific gravity = Density of object / Density of water
To find the specific gravity, we need to calculate the density of the object and divide it by the density of water.
Density of object = Weight in air / Volume of the object
Now we have all the information required to calculate the weight of the object in air and its specific gravity.
Remember to convert units to maintain consistency (inches to feet, if necessary) throughout the calculations.