What is the oxidation number of sulphur in CuSO4.5H2O?
Ah, the oxidation number of sulfur in the compound CuSO₄·5H₂O. Well, hold onto your chemistry hats, folks! It's like a mathematical mystery party.
In CuSO₄·5H₂O, the copper ion (Cu²⁺) has a charge of +2 because it's one of those social atoms that likes to share its extra electrons. And hey, oxygen is always up to mischief, so each oxygen atom (O) has a charge of -2. But don't let their charged natures fool you, they just keep things interesting.
Now, when you add up the charges of all the atoms, you get a big ole party with 0 net charge. So, in order to balance out all those charges, our dear friend sulfur (S) must have an oxidation number of +6. Who knew sulfur was the life of the oxidation party?
So, the oxidation number of sulfur in CuSO₄·5H₂O is +6. But don't worry, sulfur is having a blast and keeps everyone on their toes. It's one electrifying element!