A nuclear plant on a submarine produces steam at 350C to drive a steam electric turbine. the temperature on the low side of the turbine is 27C. how much energy is dissipated as waste heat
To calculate the amount of energy dissipated as waste heat, we can use the equation:
Q = m * c * ΔT
Where:
Q is the heat energy
m is the mass of the steam
c is the specific heat capacity of the steam
ΔT is the change in temperature between the high and low sides of the turbine
First, we need to find the temperature difference, ΔT:
ΔT = (350C - 27C)
ΔT = 323C
Now, we need to find the specific heat capacity of the steam, c. The specific heat capacity of water, which is similar to steam, is approximately 4.18 J/g°C.
Assuming the mass of the steam is 1 gram (since we don't have the actual mass), we can calculate the total heat energy:
Q = (1g) * (4.18 J/g°C) * (323C)
Q = 1329.14 J
Therefore, approximately 1329.14 Joules of energy is dissipated as waste heat.