A swimming pool whos surface forms a rectangle measures 25 m long by 15 m wide The pool is 2 m deep at the shallow end and the depth increases at a constant rate to 4 m deep at the other end How many?
How many .... what ???
I assume you are asking for the rate of increase of the depth.
for the of length 25 m, the depth increases by 2 m
so the depth increases 1 m per 12.5 m of length
notice the width has nothing to do with it.
To find the answer to your question, we need to calculate the volume of the swimming pool.
The swimming pool can be visualized as a rectangular prism with varying depth.
Step 1: Calculate the average depth of the pool.
To find the average depth, we can add the shallow end depth and the deep end depth, then divide by 2.
Average depth = (2 m + 4 m) / 2 = 6 m / 2 = 3 m
Step 2: Calculate the volume of the pool using the formula: Volume = length × width × average depth
Volume = 25 m × 15 m × 3 m = 1125 cubic meters
Therefore, the swimming pool has a volume of 1125 cubic meters.