What is the group 3A element that forms the most basic oxide? I thought it was TI, why isn't it? thanks

I would have thought so too. If it actually isn't, please repost when you find out what it is and why "it" is stronger than TlOH.

The group 3A elements in the periodic table are boron (B), aluminum (Al), gallium (Ga), indium (In), and thallium (Tl). Boron does not form an oxide in the same way as the rest of the group. Instead, it forms covalent compounds such as boron trioxide (B2O3).

The most basic oxide among the group 3A elements is actually thallium (Tl). Thallium forms thallium(I) oxide (Tl2O), which is a basic oxide because it readily reacts with water to form hydroxide ions (OH-). This reaction produces a basic solution.

To determine which element forms the most basic oxide, we can look at the periodic trends. As we move down the group, the metallic character increases, meaning the elements tend to become more basic. Thallium, being the heaviest element in group 3A, has the greatest metallic character, making its oxide the most basic among the group.

Therefore, the correct group 3A element that forms the most basic oxide is thallium (Tl).