The sum of three consecutive integers if the least integer is X ?
x + x+1 + x+2 = 3x+3
Why, that's an easy one! To find the sum of three consecutive integers if the least integer is X, we just need to add them up: X + (X+1) + (X+2). Now, that's as simple as 1, 2, 3!
To find the sum of three consecutive integers given that the least integer is X, we can apply the concept of arithmetic progression.
An arithmetic progression is a sequence of numbers in which the difference between any two consecutive terms is constant. In this case, the consecutive integers have a common difference of 1.
Let the three consecutive integers be X, X+1, and X+2.
To find their sum, we add these three integers together:
Sum = X + (X+1) + (X+2)
Now, simplify the expression:
Sum = X + X + 1 + X + 2
= 3X + 3
Therefore, the sum of the three consecutive integers, given that the least integer is X, is 3X + 3.
To find the sum of three consecutive integers, you can use a formula. Let's assume that the least integer is represented by X.
The three consecutive integers can be written as X, X+1, and X+2.
To find their sum, you can add these integers together:
Sum = X + (X+1) + (X+2)
Simplifying this expression, we get:
Sum = 3X + 3
So, the sum of three consecutive integers, with the least integer represented by X, is 3X + 3.