How would you work out this problem?
2x+5y=10
Do you have to solve for x or y? I have an algebra book... I'll post another response soon.
no.
you gotta solve for y.
y=mx+b
Okay, I see. First take 2x away from both sides. That makes:
5y= 10-2x
Now, I'm not positive about this part, but I think you would divide the whole side by 5, therefore making:
y = 2-.4x
or
y = -.4x + 2
Hope I helped!
y = mx+b , that's the equation
so
we do this
5y = 10-2x
5y = -2x + 10
now we want to get rip of the 5 in the Y
so we do
-2x / 5
10 / 5
so its -0.4 and 2
so y= -0.4x + 2
get it?
Can you answer this question
which equation represents the direct variation relationship of the equation x/y=1/2
the answer choices are
A-y=2x
B-x=2y
C-y=3x
D-y=x+1/2
and can you show the work
how do you solve linears
-x+2y=6
the output of a finction is more 5 more than 2 times the input. find the input when the output is 17.
To solve the equation 2x + 5y = 10, there are a few methods you can use, such as substitution, elimination, or graphing. Here, I will explain the substitution method.
Step 1: Solve one of the equations for one variable.
In this case, let's solve the equation for x. To do this, subtract 5y from both sides:
2x = 10 - 5y
Step 2: Solve for the other variable.
Divide both sides of the equation by 2:
x = (10 - 5y) / 2
Step 3: Substitute the expression obtained in step 2 into the other equation.
Replace x in the equation 2x + 5y = 10 with the expression we found:
2((10 - 5y) / 2) + 5y = 10
Step 4: Simplify and solve for y.
Multiply 2 with the expression inside the parentheses:
10 - 5y + 5y = 10
The y term cancels out, which means the value of y doesn't matter in this equation. We're left with:
10 = 10
Step 5: Determine the solution.
Since the equation 10 = 10 is always true, this means that the original equation 2x + 5y = 10 has infinitely many solutions. In this case, any x and y values that satisfy the equation are valid solutions.