1,500J of heat energy is added to ice water and it causes the water temperature to rise by 4°C (not 40°C).what is the Mass of the ice water?
500 = m (heat of fusion + specific heat of water*4 deg)
To find the mass of the ice water, we can use the equation Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
In this case, the heat energy added to the ice water is 1,500 J, and the change in temperature is 4°C.
Assuming no heat is lost to the surroundings, we can use the specific heat capacity of water, which is approximately 4.18 J/g°C. Let's denote the mass of the ice water as "m".
So, we can rearrange the equation as follows:
Q = mcΔT
1,500 J = m * 4.18 J/g°C * 4°C
First, multiply 4.18 J/g°C by 4°C:
1,500 J = m * 16.72 J/g
Next, divide both sides of the equation by 16.72 J/g:
m = 1,500 J / 16.72 J/g
Calculating this, we find:
m ≈ 89.86 g
Therefore, the mass of the ice water is approximately 89.86 grams.