A man has 37 coins in his pocket, all which are dimes and quarters. If the total value of his change is $6.70, how many dimes and how many quarters does he have?
Let x represent the number of dimes and y represent the number of quarters.
its asking me just to set up the equations i would use to solve, and not to solve
____=37
____=6.70
x + y = 37
0.1x + 0.25y = 6.70
Thank you!
You're welcome.
To set up the equations to solve this problem, you can use the following information:
First, we know that the man has a total of 37 coins, which includes dimes and quarters. Therefore, the equation for the total number of coins can be written as:
x + y = 37
Next, we know that the total value of his change is $6.70. Since a dime is worth $0.10 and a quarter is worth $0.25, we can set up the equation for the total value as:
0.10x + 0.25y = 6.70
So, the two equations that can be used to solve this problem are:
x + y = 37
0.10x + 0.25y = 6.70
Now, with these two equations, you can proceed to solve for x and y to find the number of dimes and quarters the man has.