what is the % (m/m) of Mg(NO3)2 in solution when 0.84 g of Mg(NO3)2 are dissolved in enough deionized water to prepare 500.0 ml of solution ( assume the solution in dilute enough that the density of the solution is 1.0 g/ml)
% m/m = grams solute/g solution.
You have 0.84 g solute and 500 solution.(density soln is 1.0 g/ml. You have 500 mL and 500 mL x 1.0 g/mL = 500 grams).
To calculate the mass percent (m/m) of Mg(NO3)2 in the solution, you need to divide the mass of Mg(NO3)2 by the total mass of the solution and then multiply by 100.
Step 1: Calculate the mass of Mg(NO3)2:
The given mass of Mg(NO3)2 is 0.84 g.
Step 2: Calculate the total mass of the solution:
The volume of the solution is given as 500.0 ml, and since the density is 1.0 g/ml, the mass of the solution can be calculated by multiplying the volume by the density:
Mass of solution = 500.0 ml × 1.0 g/ml = 500.0 g
Step 3: Calculate the mass percent (m/m) of Mg(NO3)2:
Mass percent = (mass of Mg(NO3)2 / mass of solution) × 100
Plugging in the values:
Mass percent = (0.84 g / 500.0 g) × 100
Now you can solve for the mass percent.