two arithmetic progression are such that the common difference of both is 8.if the difference b/w their 50th terms is 50.what will be the difference b/w their 80th terms?
let the first term of the first progression be a
let the 2nd term of the other progression be b
a + 49(8) - (b + 49(8)) = 50
a - b = 50
a+79(8) - (b+79(8))
= a - b
= 50
The difference between like term numbers stays the same at 50
This isn't the correct solution.
To find the difference between the 80th terms of two arithmetic progressions with a common difference of 8, we need to use the formula for the nth term of an arithmetic progression:
nth term = first term + (n - 1) * common difference
Let's denote the first term of the first arithmetic progression as a, and the first term of the second arithmetic progression as b.
We know that the common difference for both progressions is 8. Therefore, the 50th terms of the progressions can be expressed as:
a + (50 - 1) * 8 = a + 49 * 8
b + (50 - 1) * 8 = b + 49 * 8
Given that the difference between these two terms is 50, we can set up the equation:
(b + 49 * 8) - (a + 49 * 8) = 50
Simplifying this equation, we get:
b - a = 50
So, the difference between the 80th terms of the two arithmetic progressions will also be 50.
Hey u tell how it happened like that if u tell it directly how can we understand? U don't have that much common sense.
So tell how it happened and get lost u bloody hell ✌.