You are approaching a stoplight. If the frequency of the light being emitted is approximately 520 THz, what was the wavelength of the light? What color was the light?

v = c/λ

520 THz --> 5.2x10^14 Hz

5.2x10^14 Hz = 3.0x10^8 m/s

λ = 1.56 x 10^23 m

Not sure how to get the color of the light from here.

First you need to calculate the wavelength correctly.I can't make the symbols you did but it is

c = freq x wavelength
3E8 = 5.2E14 x wavelength
wavelength = 3E8/5.2E14 = 5.77E-7 m and that converted to 577E-9 m (or 577 nm). Here is a chart that will show you the color. It's yellow-orange.
https://science-edu.larc.nasa.gov/EDDOCS/Wavelengths_for_Colors.html

To determine the color of light based on its wavelength, you can refer to the electromagnetic spectrum and the visible light spectrum.

In the visible light spectrum, different colors correspond to specific ranges of wavelengths. Here are the approximate ranges:

- Red: 620-750 nm
- Orange: 590-620 nm
- Yellow: 570-590 nm
- Green: 495-570 nm
- Blue: 450-495 nm
- Indigo: 420-450 nm
- Violet: 380-420 nm

Considering the wavelength calculated earlier (1.56 x 10^23 m), it falls outside the range of any visible color. Therefore, it is not possible to determine the exact color of the light emitted by the stoplight based solely on its frequency and wavelength.

To determine the color of the light, we can use the concept of the electromagnetic spectrum and associate different wavelengths with different colors. The visible light spectrum ranges from approximately 400 to 700 nanometers (nm), with shorter wavelengths associated with blues and violets, and longer wavelengths associated with reds.

To find the color of the light with a given wavelength, we need to convert the wavelength from meters to nanometers. Since 1 meter is equal to 1x10^9 nanometers, we can multiply the wavelength in meters by 1x10^9 to convert it to nanometers.

1.56 x 10^23 m * 1x10^9 nm/m = 1.56 x 10^32 nm

The wavelength of 1.56 x 10^23 m light is approximately 1.56 x 10^32 nm.

Since this wavelength is well beyond the visible light range (400 to 700 nm), it means that the light is not visible to the human eye. It falls into the category of electromagnetic radiation beyond the visible spectrum, such as ultraviolet or infrared.