Markus had M dollars in his bank account. After removing 1/5 of the money in the account and then removing another 200, Markus now had 800. How much money did Markus have initially?
M - M/5 - 200 = 800
To solve this problem, we can set up an equation based on the given information.
Let's assume that Markus had X dollars initially.
According to the problem, Markus first removes 1/5 of the money in the account. This can be represented as: X - (1/5)X.
Next, Markus removes another 200 dollars from the remaining amount. So, the amount left in the account can be represented as: (X - (1/5)X) - 200.
According to the problem, after all the money has been removed, Markus has 800 dollars left. So, we can set up the equation:
(X - (1/5)X) - 200 = 800.
Now, let's solve the equation to find the value of X, which represents the initial amount of money Markus had.
(X - (1/5)X) - 200 = 800.
Multiplying both sides of the equation by 5 to eliminate the fraction:
5(X - (1/5)X) - 200(5) = 800(5).
5X - X - 1000 = 4000.
4X - 1000 = 4000.
Adding 1000 to both sides of the equation:
4X - 1000 + 1000 = 4000 + 1000.
4X = 5000.
Dividing both sides of the equation by 4:
(4X)/4 = 5000/4.
X = 1250.
Therefore, Markus initially had 1250 dollars in his bank account.