how do i solve these?

9^(-x)=1/3

2^(2x)+ 2^(x) -12 = 0

(3/5)^x = 7 ^ (1-x)

9^(-x)=1/3

(3^2)^(-x) = 3^-1
3^(-2x) = 3^-1
so -2x = -1
x = 1/2

2^(2x)+ 2^(x) -12 = 0
(2^x)^2 + 2^x - 12 = 0
let y = 2^x

y^2 + y - 12 = 0
(y+4)(y-3) = 0
y = -4 or y = 3

2^x = -4, no solution , or
2^x = 3 --- x = log3/log2

last one:

take logs of both sides

(3/5)^x = 7 ^ (1-x)
log(3/5)^x = log7 ^ (1-x)
xlog(3/5) = (1-x)Log 7
xlog .6 = log 7 - xlog 7
xlog .6 + xlog 7 = log 7
x(log .6 + log 7) = log 7
x = log 7/(log.6 + log7)

1/6

wcqylfho plxkesdjc meloifxus gleusp syzoqk pbxuj tgeo

To solve these equations, we'll need to apply some algebraic techniques. Let's go through each equation step-by-step:

1. 9^(-x) = 1/3:

To start, let's rewrite 1/3 as a power of 9. We know that 1/3 is the same as 3^(-1), so we can rewrite the equation as:

9^(-x) = 3^(-1)

Next, we can rewrite both sides using the same base:

(3^2)^(-x) = 3^(-1)

Now, apply the property of exponents that states (a^b)^c = a^(b * c):

3^(-2x) = 3^(-1)

Since the bases are the same, we can conclude that:

-2x = -1

Now, isolate x by dividing both sides of the equation by -2:

x = (-1) / (-2)

Simplifying the right side gives us:

x = 1/2

2. 2^(2x) + 2^x - 12 = 0:

Notice that we have a quadratic equation in terms of 2^x. We can make a substitution to simplify it:

Let y = 2^x.

Now our equation becomes:

y^2 + y - 12 = 0

Factor the quadratic equation:

(y + 4)(y - 3) = 0

Set each factor equal to zero:

y + 4 = 0 --> y = -4

y - 3 = 0 --> y = 3

Substitute back y = 2^x:

2^x = -4 and 2^x = 3

However, we cannot have negative values for 2^x, so we discard the solution 2^x = -4.

Now solve 2^x = 3:

Take the logarithm (base 2) of both sides of the equation:

x = log2(3)

Use the change of base formula for logarithms:

x = log(3) / log(2)

Approximately, x = 1.585


3. (3/5)^x = 7^(1-x):

To compare the bases of this equation, we can write 7 as (7/1):

(3/5)^x = (7/1)^(1-x)

Now, we can rewrite both sides using the same base:

(3/5)^x = (3/5)^(4-2x)

Since the bases are the same, we can equate the exponents:

x = 4 - 2x

Combine like terms:

3x = 4

Solve for x by dividing both sides by 3:

x = 4/3

Hence, the solution is x = 4/3.