The graph represents the cost cc (in dollars) of buying nn tickets to a baseball game.

(1,10) (2,20) (3,30)

a. Should the points be connected with a line to show all the solutions? Explain your reasoning.
make sense to draw a line between the points to show all of the solutions. You sell part of a ticket.

Question 2
b. Write an equation in two variables that represents the graph.
c=c=

Bruh-

Can we just get a strait answer please.

a. It does not make sense to connect the points with a line to show all the solutions because the given points do not form a linear relationship. In a linear relationship, the value of one variable (in this case, the number of tickets) will change at a constant rate with respect to the other variable (in this case, the cost). However, in this scenario, the cost is directly proportional to the number of tickets, meaning that for each additional ticket, the cost increases by a fixed amount. Hence, drawing a line between the points would not accurately represent this relationship.

b. To write an equation in two variables that represents the graph, let's assume that the equation is of the form c = mx, where c represents the cost and x represents the number of tickets. Since the cost increases by a fixed amount for each ticket, we can find the slope (m) by taking the difference in costs and dividing it by the difference in the number of tickets.

Using the given points (1, 10) and (2, 20), the difference in the costs is 20 - 10 = 10, and the difference in the number of tickets is 2 - 1 = 1.

Therefore, the slope (m) is 10/1 = 10.

Now, we can use one of the given points to find the y-intercept (c) by substituting the values into the equation c = mx. Let's use the point (1, 10):

10 = 10(1)
10 = 10

Hence, the equation in two variables that represents the graph is c = 10x.

c. The correct equation that represents the graph is c = 10x.

a line will not reflect the reality, as it will include fractional values. Only integer numbers of tickets can be used.

Surely you can see the relationship between c and b.

No