if one of the zeroes of a cubic polynomial x^3+ax^2+bx+c is -1.find the product of other 2 zeroes
if the zeros are p,q,r then pqr=c
To find the product of the other two zeros of the cubic polynomial \(x^3 + ax^2 + bx + c\) when one of the zeros is \(-1\), we can use the fact that the sum of the zeros of a cubic polynomial is equal to the negation of the coefficient of the quadratic term divided by the coefficient of the cubic term.
Let's denote the other two zeros as \(p\) and \(q\). Given that one of the zeros is \(-1\), we have the sum of the three zeros as \(-1 + p + q\). According to Vieta's formulas, this sum is equal to \(-a\) divided by \(1\):
\(-1 + p + q = -a/1\)
Since we only know that \(-1\) is a zero, we need to find the value of \(a\) in order to proceed with finding the product.
Is there any additional information or coefficients of the polynomial that you can provide to help find the value of \(a\) and solve the problem?