How many ml of HCl required to prepare 5% of HCl solution in 750ml water.if HCl is 36% pure and specific gravity is 1.18g/ml?

What is the molarity (M) of the HCl? That's

1000 mL x 1.18 g/mL x 0.36 x (1/36.5) = ?
Then use mL1 x M1 = mL2 x M2. Substitute and solve for the unknown. Post your work if you get stuck.

To find out how many milliliters of HCl are required to prepare a 5% HCl solution in 750 ml of water, we need to consider the purity and specific gravity of the HCl.

Here's the step-by-step calculation:

1. Determine the amount of HCl needed for a 5% solution:
- A 5% HCl solution means that 5 grams of HCl are dissolved in 100 ml of solution.
- Therefore, for 750 ml of solution, the amount of HCl needed would be:
(5 grams / 100 ml) * 750 ml = 37.5 grams of HCl

2. Convert grams of HCl to milliliters of HCl using the specific gravity:
- The specific gravity of HCl is 1.18 g/ml, which means that 1 milliliter of HCl weighs 1.18 grams.
- So, to determine the volume of HCl needed, divide the mass (grams) by the specific gravity (grams/milliliter):
37.5 grams / 1.18 g/ml = approximately 31.78 milliliters of HCl

Therefore, approximately 31.78 milliliters of HCl are required to prepare a 5% HCl solution in 750 ml of water.