15(5x-2)=82x+1
solve the extraneous root
No extraneous root here.
Just a simple equation.
opss i typed it wrong
15(5^x-2)=8^2x+1
I sent it through Wolfram the way you typed it
Even Wolfram had trouble understanding what you meant:
http://www.wolframalpha.com/input/?i=solve+15(5%5Ex-2)%3D8%5E2x%2B1
To solve the equation 15(5x-2)=82x+1 and determine if there are any extraneous roots, we need to follow these steps:
Step 1: Distribute on the left side of the equation:
75x - 30 = 82x + 1.
Step 2: Simplify the equation by combining like terms:
75x - 82x = 1 + 30,
-7x = 31.
Step 3: Divide both sides of the equation by -7 to isolate x:
-7x / -7 = 31 / -7,
x = -31/7.
After solving the equation, we find that the value of x is -31/7. However, this is the only solution to the equation, so there are no extraneous roots in this case.