a door is fixed with the support the length of the door is 3.3foot. the handle is attached at o.3foot. from a side opposiite to the side of hinches. it is opened with the torque of 5Nm. how much force is needed
To calculate the force required to open the door, we need to use the formula for torque.
Torque (τ) is the product of the force (F) applied to an object and the distance (r) from the pivot point at which the force is applied:
τ = F * r
In this case, the torque required to open the door is given as 5 Nm (Newton-meters), and the distance from the pivot point (hinges) to the point where the force is applied (handle) is given as 0.3 feet.
First, we need to convert the distance from feet to meters. Since 1 foot is equal to 0.3048 meters, the distance is 0.3 * 0.3048 = 0.09144 meters.
Next, we rearrange the torque formula to solve for force:
F = τ / r
Plugging the values into the formula, we get:
F = 5 Nm / 0.09144 meters
Calculating the result:
F ≈ 54.64 Newtons
Therefore, approximately 54.64 Newtons of force is needed to open the door.